Math, asked by swati14333, 1 year ago

please solve it fast...​

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Answers

Answered by Anonymous
14

Answer:

LHS = tan A ( 1 + sec 2A )

.......= tan A ( 1 + 1/ cos 2A )

.......= tan A ( cos 2A + 1 ) / ( cos 2A )

.......= tan A ( 2 cos^2 A ) / ( cos 2A )

......= ( sin A / cos A ) ( 2 cos^2 A ) / ( cos 2A )

.......= ( 2 sin A cos A ) / cos 2A

.......= sin 2A / cos 2A

.......= tan 2A

........=RHS

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