Question

Please solve it fast​

Answer 1

ANSWER:

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$1\:\:+\:\:\frac{tan²\:A}{1\:\:+\:\:sec\:A}\:=\:sec\:A$

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SOLUTION:

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$1\:+\:\frac{tab²\:A}{1\:+\:sec\:A}\:sec\:A$

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$1\:+\:\frac{tan²\:A}{1\:+\:sec\:A}\:=\:1\:+\:\frac{(sec²\:A\:-\:1)}{1\:+\:sec\:A}$

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$=\:1\:+\:\frac{(sec\:A\:\:-\:\:1)\:(sec\:A\:\:+\:\:1)}{(1\:+\:sec\:A)}$

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$=\:1\:+\:sec\:A\:\:-\:\:1$

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$1\:\:+\:\:\frac{tan²\:A}{1\:\:+\:\:sec\:A}\:=\:sec\:A$

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Done