Please solve it fast
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I think answer will be c=3p/2
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papakiladli5:
ohhh sorry
it's my fault
sorry anjali3994
that I gave you wrong answer
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x² - p(x+1)-c = x² -px+p -c
compare it with ax²+bx+c =0
a= 1, b= -p , c= p-c
α and β are two zeroes
i) sum of the zeros= -b/a
α+β = - (-p)/1= p -----(1)
ii) product of the zeroes = c/a
αβ = (p-c) /1 = p-c -----(2)
now take
lhs = (α+1)(β+1)
0= α(β+1) +1(β+1)
0=αβ +α +β +1
0=p-c+p+1 [from (2) and (1) ]
0= 2p-c+1
c=2p+1
compare it with ax²+bx+c =0
a= 1, b= -p , c= p-c
α and β are two zeroes
i) sum of the zeros= -b/a
α+β = - (-p)/1= p -----(1)
ii) product of the zeroes = c/a
αβ = (p-c) /1 = p-c -----(2)
now take
lhs = (α+1)(β+1)
0= α(β+1) +1(β+1)
0=αβ +α +β +1
0=p-c+p+1 [from (2) and (1) ]
0= 2p-c+1
c=2p+1
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