please solve it fast 6 question
it is 1 mark question
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angle is 90
because you'll find the other side using Pythagoras therom for the inside triangle.then you gotta prov that the sum of squares of the two side is equal to the side opposite to the angle.it will b equal.thn by converse Pythagoras therom,u get the answer
because you'll find the other side using Pythagoras therom for the inside triangle.then you gotta prov that the sum of squares of the two side is equal to the side opposite to the angle.it will b equal.thn by converse Pythagoras therom,u get the answer
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in triangle PAR
by pythagorus theorom
(AP)^2 + (AR)^2 = (PR)^2
(6)^2 + (8)^2 = (PR)^2
PR = 10cm
now in triangle PQR
L.H.S
--------
(PQ)^2 + (PR)^2 = (24)^2 + (10)^2
576 + 100 = 676
now
R.H.S
---------
(QR)^2 = (26)^2 = 676
as
L.H.S = R.H.S
so
by converse of pythagorus theorom
angle(QPR) = 90°
by pythagorus theorom
(AP)^2 + (AR)^2 = (PR)^2
(6)^2 + (8)^2 = (PR)^2
PR = 10cm
now in triangle PQR
L.H.S
--------
(PQ)^2 + (PR)^2 = (24)^2 + (10)^2
576 + 100 = 676
now
R.H.S
---------
(QR)^2 = (26)^2 = 676
as
L.H.S = R.H.S
so
by converse of pythagorus theorom
angle(QPR) = 90°
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