Please solve it fastly and tell me the answer
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ADB = 180° - 100° = 80°
By remote interior angle theorem,
@ + ß = 80° ...(i)
2@ + ß = 100° (ii)
Subtracting (i)&(ii),
@ = 20° . So, ß = 60°
By comparing the above results we get that option (D) is not correct.
Checking,
sin(ß-@) = 1/√2
sin(60°-20°) = 1/√2
sin(40°) = 1/√2
but, sin40°≠1/√2
hence it's wrong.
i.e., the answer is option D.
By remote interior angle theorem,
@ + ß = 80° ...(i)
2@ + ß = 100° (ii)
Subtracting (i)&(ii),
@ = 20° . So, ß = 60°
By comparing the above results we get that option (D) is not correct.
Checking,
sin(ß-@) = 1/√2
sin(60°-20°) = 1/√2
sin(40°) = 1/√2
but, sin40°≠1/√2
hence it's wrong.
i.e., the answer is option D.
Answered by
0
(A) why,cause the angle dose not 2 degree it is 20 degree
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