Question

please solve it for me

Answer 1

Answer to your question:

Answer 2

$\mathsf{Given\:Equation}:\dfrac{1-x}{3}-\dfrac{3}{2}\bigg[ 2 -\dfrac{x-5}{2} \bigg] +\dfrac{x+3}{4}=1\\\\\\\\\implies \dfrac{1-x}{3} -\dfrac{3}{2}\bigg[ \dfrac{4-(x-5)}{2}\bigg] + \dfrac{x+3}{4}=1\\\\\\\implies \dfrac{1-x}{3} -\dfrac{3}{2} \bigg[ \dfrac{4 - x + 5}{2} \bigg]+ \dfrac{x+3}{4}=1\\\\\\\implies \dfrac{1-x}{3} - \dfrac{3}{2} \bigg[ \dfrac{9-x}{2} \bigg] + \dfrac{x+3}{4} = 1 \\\\\\\implies \dfrac{1-x}{3}-\dfrac{27-3x}{4} + \dfrac{x+3}{4} = 1$

$\implies \dfrac{ 4(1-x)-3(27-3x)+3(x+3)}{12}=1\\\\\\\implies 4 - 4x - 81 + 9x + 3x + 9 = 12 \\\\\implies - 4x + 9x + 3x +4 - 81 + 9 = 12 \\\\\implies 8x - 68 = 12 \\\\\implies 8x = 12 + 68 \\\\\implies 8x = 80\\\\\implies x =\dfrac{80}{8} \\\\\\\implies x = 10$

Therefore the value of x satisfying the given equation is 10.