Question

Please solve it.........
I will mark u BRAINLIEST

Answer 1

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## HERE'S YOUR ANSWER ##

THE ANSWER OF YOUR QUESTION IS 1.

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Answer 2

Answer:

1

Step-by-step explanation:

$\frac{3}{x+2} - \frac{1}{x+1} = \frac{2}{x+3} \\ \\ \frac{3(x+1) - 1(x+2)}{(x+2)(x+1)} = \frac{2}{x+3} \\ \\ \frac{3x+3-x-2}{x^2+3x+2} = \frac{2}{x+3} \\ \\ \frac{2x+1}{x^2+3x+2} = \frac{2}{x+3}$

$(2x+1)(x+3) = 2(x^2+3x+2) \\ \\ 2x^2+7x+3 = 2x^2+6x+4 \\ \\ 2x^2+7x+3-2x^2-6x-4=0 \\ \\ x-1=0 \\ \\ x=\bold{1}$

∴ 1 is the answer.

Thank you. Have a nice day. :-)

#adithyasajeevan