Question

please solve it it is so urgent for me​

Answer 1

Answer:

Area of the given figure is 36.75 cm^2.

Step-by-step explanation:

On the basis of the information given in this question :

• Length of DP = MP - MD = 9 cm - 7 cm = 2 cm
• Length of CP = MP - MC = 9 cm - 6 cm = 3 cm
• Length of BD = MP - MB - DP = 9 cm - 4 cm - 2 cm = 3 cm
• Length of AC = MP - MA - CP = 9 cm - 2 cm - 3 cm = 4 cm
• Area of triangle = 1 / 2 x height x base
• Area of trapezium = 1 / 2 x ( sum of parallel sides ) x height

For the areas for all the right-angled triangles :

= > Area of QPD = 1 / 2 x 2 cm x DP = 1 / 2 x 2 cm x 2 cm = 2 cm^2

= > Area of OCP = 1 / 2 x 4 cm x CP = 1 / 2 x 4 cm x 3 cm = 6 cm^2

= > Area of MAN = 1 / 2 x 2 cm x 3 cm = 3 cm^2

= > Area of RBM = 1 / 2 x 2.5 cm x 4 cm = 5 cm^2

For the areas of both the trapeziums :

= > Area of OCAN = 1 / 2 x ( 4 cm + 3 cm ) x AC = 1 / 2 x 7 cm x 4 cm = 14 cm^2

= > Area of QRBD = 1 / 2 x ( 2 cm + 2.5 cm ) x BD = 1 / 2 x 4.5 cm x 3 cm = 6.75 cm^2

Thus,

= > Area of the given figure = 2 cm^2 + 6 cm^2 + 3 cm^2 + 5 cm^2 + 14 cm^2 + 6.75 cm^2 = 36.75 cm^2

Hence, area of the given figure is 36.75 cm^2.