Question

please solve it ... it's urgent.​

Answer 1

$\huge\boxed{\texttt{\fcolorbox{red}{aqua}{Answer :-}}}$

Step-by-step explanation:

$= > {(x + y)}^{2} = {x}^{2} + {y}^{2} + 2xy \\ = > ( \sqrt{11} ) {}^{2} = 6 + 2xy \\ = > 11 = 6 + 2xy \\ = > 5 = 2xy \\ = > xy = 2.5 \\ \\ also \\ = > x + y = \sqrt{11} \\ so \\ = > x + \frac{2.5}{x} = \sqrt{11} \\ = > \frac{ {x}^{2} + 2.5 }{x} = \sqrt{11} \\ = > {x}^{2} + 2.5 = x \sqrt{11} \\ = > {x}^{2} - x \sqrt{11} + 2.5 = 0 \\ so \\ = > x = \frac{ - b {}^{2} \binom{ + }{ - } \sqrt{4ac} }{2a}$

So You Can Solve The Equation By Given Formula........ And Find x