Question

please solve it questions 16

Answer 1

hey mate...

as clearly seen in the figure..

7ohm nd 10 ohm are is series..
therefore net is 10+7 =17ohm
now,
4ohm nd 2 ohm are also in series on other side..
therefore their net will be 4+2=6ohm
now see
17ohm 6ohm and the middle wire of 6ohm are in parallel...
apply formula for parallel combination of resistance..
1/R = 1/17 + 1/6 + 1/6 ....solve it and get the required answer ....

hope it helps u..

Answer 2

let r1 = 2 ohm, r2 = 4ohm , r3= 6 ohm , r4= 7 ohm and r5 = 10 ohms   now,,    r1 and r2 are in series   --> 2+4 =6 ohms = Rs1  Rs1 and r3 are in parallel --> 1/Rp1 = 1/Rs1 + 1/r3                = 1/6 + 1/6                = 1/3      Rp1 = 3 ohms  --> r4 and r5 are in series and is parallel  with Rp1  => 10 + 7 = 17 ohms  in parallel, 1/17 + 1/3           = 3+17/51            = 20/51           = 0.3 ohms  the equivalent  resistance of the circuit is 0.3 ohms..    #hope it helps #mark as brainliest pls