Math, asked by Avash7152, 7 months ago

please solve it quickly

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Answers

Answered by vishu6306342671
0

Answer:

(sinx+cosx)(sin^2x+cos^2x-sinx coax) /sinx+cosx +(sinx-cosx) (sin^2x+cos^2x+sinx coax) /sinx-cosx

1-sinx coax +1+sinx cosx

=2

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