Math, asked by thakurji80, 11 months ago

please solve it's very urgent​

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Answered by lucy228
2

Answer:

using identity ( a+b+ c) square = a square + b square + c square + 2ab + 2bc+ 2ca.

(-√2x square ) + y Square + 2 ×√2z square + 2× -√2x × y + 2 × y×2√2z + 2× -√2 × 2 √2z

( -√2x + y + 2√ 2z ) square

(- √2x + y + 2√ 2z ) ( - √ 2x + y + 2√ 2z)

hope this will help u

good luck

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