Question

please solve it!!!!
Solve (3-4i)(x+yi)=1+0.i for real numbers x and y, where i=√-1​

Answer 1

Step-by-step explanation:

(3-4i)(x+yi)

=3x+3yi-4x-4yi^2

=(3x+4y)+(-4x+3y)i=1+0*i

equating real and imagenary part.

3x+4y=1 and 3y-4x=0

By solving these equations,

We get, x=0.12,y=0.16