Math, asked by J1TENDRA, 1 year ago

please solve it step by step​

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Answered by abhi569
2

Answer:

Left Hand Side = Right Hand Side

Step-by-step explanation:

Left Hand Side :

\implies log \dfrac{a^2}{bc}+log\dfrac{b^2}{ac}+log\dfrac{c^2}{ab}From the properties of logarithms : log a + log b + log c = log abc Thus,\implies log\bigg\{ \dfrac{a^2}{bc}\times \dfrac{b^2}{ac}\times\dfrac{c^2}{ab}\bigg\} \\\\\\\implies log\bigg\{ \dfrac{a^2 \times b^2 \times c^2 }{ ab \times bc \times ac }\bigg\}\\\\\\\implies log\bigg\{ \dfrac{a^2 b^2 c^2}{a^2b^2c^2}\bigg\} \\\\\\\implies log 1

From the properties of logarithms we know log 1 is equal to 0. Thus,

= > 0

Hence, 0 = 0

Left Hand Side = Right Hand Side

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