Please solve it... Urgent..10 points....
Attachments:
![](https://hi-static.z-dn.net/files/d37/3bc3dc0cc45887441030ae9618baf7d8.jpg)
Answers
Answered by
1
Answer:
mark as brainliest red will be to u
Attachments:
![](https://hi-static.z-dn.net/files/df5/262ff99bf3eed569cb8ece1b36e65aa3.jpg)
Answered by
5
Answer:
Given PS=PR,∠TPS=∠QPR
we have to prove that PT=PQ
In△PSR,
PS=PR(given)
∴∠PSR=∠PRS−(i)
{ Angles opposite to equal sides of a △le are equal}
∴∠TPS+∠PTS=∠QPR+∠PQR
(An exterior angle of a △le is equal to the sum of its two interior opposite angle)
⟹∠PTS=∠PQR
∴∠PTQ=∠PQT∴PT=PQ
(sides opposite to equal angles of a △le are equal).
Step-by-step explanation:
Plz mark me as brainliest answer
Similar questions