Question

please solve it... urgently...


no irrelevent answers...

Answer 1

Answer:

1/4

Step-by-step explanation:

Favourable outcomes = (4, 4) (4, 5) (4, 6) (5, 4) (5, 5) (5, 6) (6, 4) (6, 5) (6, 6)

No. of Favourable Outcomes = 9

Total number of outcomes = 6^2 = 36

Thus, Probability of Getting a no greater than 3 on both dies = 9/36 = 3/12 = 1/4

Hope it helps.

Answer 2

Answer:

1/4

Step-by-step explanation:

Total number of possible outcomes when two dice are thrown = 6² = 36.

Let A be the event of getting a number greater than 3 on each dice.

n(A) = {4,4},{4,5},{4,6},{5,4},{5,5},{5,6},{6,4},{6,5},{6,6}

= 9.

∴ P(A) = n(A)/n(S)

         = 9/36

        = 1/4

Hope it helps!