Two bodies of equal mass move with uniform velocity v and 3v respectively. find the ratio of their Kinetic energies
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Answered by
12
KE 1=1/2.m.v1^2
KE 2=1/2.m.v2^2
KE1/KE2
=> half and mass cancel
=> v^2/9v^2
v^2 cancel
1:9
KE 2=1/2.m.v2^2
KE1/KE2
=> half and mass cancel
=> v^2/9v^2
v^2 cancel
1:9
Answered by
18
Hi....
The kinetic energy of first body will be 1/2m(v)^2
& The kinetic energy of 2nd body will be
1/2m(3v)^2 = 1/2m9(v)^2
So their ratio will be
KE (1st body)/KE(2nd body)=
1/2m(v)^2/ 1/2m×9(v)^2 = 1/9
Therefore, the Kinetic energies of both the body are in the ratio 1:9...
Hope this helps you.... ☺
The kinetic energy of first body will be 1/2m(v)^2
& The kinetic energy of 2nd body will be
1/2m(3v)^2 = 1/2m9(v)^2
So their ratio will be
KE (1st body)/KE(2nd body)=
1/2m(v)^2/ 1/2m×9(v)^2 = 1/9
Therefore, the Kinetic energies of both the body are in the ratio 1:9...
Hope this helps you.... ☺
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