please solve it urgentt
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Step-by-step explanation:
sinA/1-cosA+tanA/1+cosA
=sinA/1-cosA+sinA/cosA(1+cosA)
=sinA{1/1-cosA+1/cosA(1+cosA)
=sinA{cosA(1+cosA)+1-cosA/cosA(1-cos²A)}
=sinA(cosA+cos²A+1-cosA/cosAsin²A)
=sinA(1+cos²A/sin²AcosA)
=1+cos²A/sinAcosA
=1/sinAcosA+cos²A/sinAcosA
=secAcosecA+cotA
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