Math, asked by ushadan, 10 months ago

please solve it urgentt

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Answered by sandy1816

0

Step-by-step explanation:

sinA/1-cosA+tanA/1+cosA

=sinA/1-cosA+sinA/cosA(1+cosA)

=sinA{1/1-cosA+1/cosA(1+cosA)

=sinA{cosA(1+cosA)+1-cosA/cosA(1-cos²A)}

=sinA(cosA+cos²A+1-cosA/cosAsin²A)

=sinA(1+cos²A/sin²AcosA)

=1+cos²A/sinAcosA

=1/sinAcosA+cos²A/sinAcosA

=secAcosecA+cotA

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