Math, asked by Anonymous, 1 year ago

Please solve it very urgent.

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Anonymous: hello what is the constant term in 7th question :/?
Anonymous: That's -15 at last in 7 question
Anonymous: ok lemme edit dear

Answers

Answered by ashmahajan
1
1.x²-3x+4x-12=0
  x(x-3)+4(x-3)=0
  (x-3)(x+4)=0
   x-3=0 or x+4=0
   x=3 or x= -4

2.x²+14x+48=0
   x²+12x+4x+48=0
   x(x+12)+4(x+12)=0
   (x+12)(x+4)=0
    x+12=0 or x+4=0
    x= -12 or x= -4

3.4x²+11x-20=0
   4x²+16x-5x-20=0
   4x(x+4)-5(x+4)=0
    (x+4)(4x-5)=0
     x+4=0 or 4x-5=0
    x= -4 or 4x=5
                   x=5/4

4.6x²-19x+8=0
   6x²-3x-16x+8=0
   3x(2x-1)-8(2x-1)=0
    (2x-1)(3x-8)=0
     2x-1 =0 or 3x-8=0
     2x=1 or 3x=8
     x=1/2  or x=8/3
 
5. 6√3x²-47x-5√3 =.0
    6√3x²-2x-45x-5√3 =0
   2x(3√3x-1)-5√3(3√3-1)=0
    (2x-5√3) (3√3x-1)=0
    2x-5√3 =0   or 3√3x-1=0
    2x=5√3        or  3√3x=1
   x=5√3/2         or  x=1/3√3
 
6.2√3x²+x-5√3=0
    2√3x²+6x-5x-5√3=0
    2√3x(x+√3)-5(x+√3)=0
    (2√3x-5) (x+√3) =0
    2√3x-5=0 or x+√3=0
     2√3x=5    or  x= -√3
     x=5/2√3    or  x= -√3

7.
8.7(x-2y)²-25(x-2y)+12=0
   let x-2y be a
   7a²-25a+12=0
    7a²-21a-4a+12=0
    7a(a-3)-4(a-3)=0
    (a-3)(7a-4)=0
    a-3 =0 or 7a-4=0
   a=3 or 7a=4
             or a=4/7

resubstituting the value of a
x-2y=3         or x-2y=4/7


9.7√2x²-10x-4√2=0
  7√2x²-14x+4x-4√2=0
   7√2x(x-√2)+4(x-√2)=0
  (7√2x+4) (x-√2)=0
  7√2x+4=0 or x-√2=0 
  7√2x=-4 or  x= √2
  x=4/7√2  or x= √2


10. 8+3x²-10x=0
    3x²-10x+8=0
    3x²-6x-4x+8=0
    3x(x-2)-4(x-2)=0
    (3x-4) (x-2)=0
   3x-4=0 or x-2=0
   3x=4   or  x=2
   x=4/3  or x=2
    
   
   

Anonymous: Thanks for answer
Answered by Anonymous
2
Hello Dear !
_________________________________________________________
Answer 1 = x² +x - 12 
                = x² + 4x - 3x -12            
                = x(x+4) -3(x+4)
                =( x+4)(x-3)

Answer 2 = x² +14x +48 
                = x² + 8x + 6x + 48 
                = x(x+8) + 6(x+8)
                = (x+8) (x+6)

Answer 3 = 4x² + 11x-20 
                = 4x² +16x-5x-20 
                = 4x(x+4)-5x(x+4)
                = (x+4) (x-5x)

Answer 4 = 6x²-19x +8
                = 6x²-16x-3x+8
                = 2x(3x-8)-1(3x-8)
                = (3x-8) (2x-1)

Answer 5 = 6√3x² - 47x + 5√3
                = 6√3x² -45x-2x +5√3
                = 3√3(2x-5√3)-1(2x-5√3)
                = (2x-5√3) (3√3-1)

Answer 6 = 2√3x² + x - 5√3
                = 2√3x² +6x -5x -5√3
                = 2√3x(x+√3)-5(x+√3)
                = (x+√3) (2√3-5)

Answer 7 = 2x² + 2√2x -15 
                 = 2x² +5√2x-3√2x-15 
                 = √2x(√2x+5)-3(√2x+5)
                 = (√2x+5) (√2x-3)

Answer 8 = 7(x-2y)² - 25(x-2y) + 12 
                = 7(x-2y)² - 28(x-2y)+3(x-2y)+12
                = 7(x-2y)[(x-2y)-4] +3[(x-2y)-4]
                =[(x-2y)-4] [7(x-2y)+3]

Answer 9 = 7√2x²-10x - 4√2
                = 7√2x²- 14x+4 x -4√2
                = 7√2x(x-√2) +4(x-√2)
                = (x-√2) (7√2x+4)

Answer10 = 3x² -10x +8 
                 = 3x² -6x-4x+8 
                 = 3x(x-2)-4(x-2)
                 = (x-2) (3x-4)
____________________________________________________________
 
It took me a lot of time few ^^" 
Hope u like it  !!!



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