Question

please solve it with explanation​

Answer 1

Answer:

refer the image attached

Explanation:

For v-t graph;

the body is thrown with a certain velocity 'v' as marked on the y-axis. It travels to a certain height and stops thus velocity becomes 0. Then it returns with the same velocity 'v' but in the opposite direction so it becomes '-v'. You can verify the graph by looking at the area under the graph. The area under the v-t graph here is 0 so the object has returned to its original position and hence the graph can be verified.

for s-t graph;

firstly the graph should be a parabola since distance is calculated by s= ut+1/2 at^2 which is a quadratic equation.

The object travels from rest so the graph should start from the origin. It reaches some maximum height when thrown and comes back down. The velocity constantly decreases when it travels upwards so the slope should be negative thus the graph should be in the 4th quadrant. the curve will go up and come down since the object travels to a certain height and returns to the ground.

for a-t graph;

the acceleration should act constantly downwards(since its gravitational acceleration) no matter in what direction the ball goes and so the graph should be constant( parallel to the x axis). the value of g will be -9.8 m/s^2

I've tried to explain everything in a concise manner. Hope that helped!

cheers mate!