Math, asked by sruthiusha2203, 3 days ago

please solve my problem

note
need explanation
don't delete my question
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gud answer mark brainliest

if you do without explanation i will not mark you as brainliest​

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Answered by ImperialRkSahu
1

(2)

1) in ∆ abc

angle <abc + <bca < cba = 180⁰ so

b + < c + 50⁰ = 180

180- 50 = 130

130/2 = 65

so ,angle b and angle c is 65

3)in ∆abc

<ABC + <BCA + <CAB = 180⁰

so,

<CAB + <BCA+ <ABC= 180

120 + <A + <ACB= 180

< BCA + < ACB = 180 - 120= 60

60/2 = 30

SO angle b and angle c is 30⁰

(<) I use symbol instead of angel symbol

plz make me brailiest I did very hard work for your answer

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