please solve my problems in math
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U can solve all of them by using these three formulas
sin(90°-A) =cos A
tan(90°-A) =cot A
Sec(90°-A) =cosec A
And u can just do inverse of them like.. cos(90°-A) =sin A and so on..
I will solve one for u to make the thing clear
7(ii) sec(90°-61°) /cosec 61° will give u cosec 61°/cosec 61° which will give one
Hope it helps!!
sin(90°-A) =cos A
tan(90°-A) =cot A
Sec(90°-A) =cosec A
And u can just do inverse of them like.. cos(90°-A) =sin A and so on..
I will solve one for u to make the thing clear
7(ii) sec(90°-61°) /cosec 61° will give u cosec 61°/cosec 61° which will give one
Hope it helps!!
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