Question

please solve my question fast it's urgent I will mark you in brainlist

Answer 1

Answer:

1536 cm^2

Step-by-step explanation:

As we know that Diagonals of a rhombus bisect each other at right angles.

Let ABCD be the rhombus.

AC = 48 cm, AB = 40 cm.

In right angled triangle AOB,

AB = 40 cm, AO = 24 cm.

By pythagorous theorem.

AB^2 = AO^2 + BO^2

⇒ (40)^2 = (24)² + BO^2

⇒ 1600 = 576 + BO^2

⇒ 1024 = BO^2

⇒ BO = 32 cm.

∴ Diagonal BD = 2 * BO

                         = 64 cm.

Area of rhombus = (1/2) * (Product of diagonals)

                            = (1/2) * (48) * 64

                            = 1536 cm^2.

Hence, Area of rhombus = 1536 cm^2.

(17)

Let the diagonal = 'x' cm.

Area of parallelogram = (1/2) * diagonal * (Sum of the lengths of the perpendicular drawn

676 = (1/2) * x * (13 + 13)

1352 = x * 26

x = 52 cm.

Hence, Diagonal = 52 cm.

Hope it helps you

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