Question

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Answer 1

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Answer 2

GIVEN : AC=7.8cm
BC=5 cm ,AD= 5cm and AB = CD = 6cm

TO PROOF : ∆ADC ≈ ∆CBA

PROOF: In ∆ADC AND ∆CBA
AD=CB (BOTH ARE EQUAL GIVEN)
DC=BA (BOTH ARE EQUAL GIVEN)
CA=AC ( COMMON )
Therefore ,
∆ADC≈∆CBA ( S.S.S CONGRUENCE RULE )
HENCE PROVED ....

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