Question

please solve no. 5 it's urgent!!!

Answer 1

let a be side of square

Area = a^2 = 121

a = 11

So perimeter of square = 4a = 4×11 = 44

Now it's bent to form circle

2 pie r = 44

2× 22/7 × r = 44

44r/7 = 44

r = 7

So area of circle = pie r^2 = 22 × 7 × 7/7

= 154

So there is change in area of 154 -121 = 33

Answer 2

${Answer :-}$

Let the one side of square be x.

So, x^2 = 121
Or, x^2 = 11 * 11
Or, x = 11.

Now, perimeter of the square = 4*11 = 44m.

So, perimeter of the square = perimeter of the circle.

Thus, 2 pi r = 44.
Or, 2 *22/7 *r = 44.
Or, r = 7.

So, area of the circle
= pi r^2
= 22/7 * 7 * 7
= 154 sq. m.

Thus, there will be increase in area by (154-121) = 33 sq. m.

Hope this helps,.

If helps, please mark it as brainliest ^_^