please solve no.vii factorisation
Attachments:
Answers
Answered by
2
(l+m) ^2-4lm=l^2+m^2+2ml-4lm
=l^2 +m^2- 2lm
(l-m)^2
=l^2 +m^2- 2lm
(l-m)^2
Answered by
0
[l+m]2 - 4lm
there is an identity for the first expression [ a2 + 2ab + b2]
[ l2 + 2 x l x m + m2 ] - 4lm
[ l2 + 2lm + m2] - 4lm
l2 + 2lm + m2 - 4lm
l2 - 2lm + m2
[l-m]2 [ ANS ]
there is an identity for the first expression [ a2 + 2ab + b2]
[ l2 + 2 x l x m + m2 ] - 4lm
[ l2 + 2lm + m2] - 4lm
l2 + 2lm + m2 - 4lm
l2 - 2lm + m2
[l-m]2 [ ANS ]
Similar questions