Question

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Answer 1

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Answer 2

Answer:

Let,

Given points A(2,2),B(4,2),C(3,0) and D(1,0)

Are vertices of a parallelogram

Step-by-step explanation:

By using distance formula :

$\sqrt{(x2 - x1) {}^{2} + (y2 - y1) {}^{2} }$

AB=

$\sqrt{(4 - 2) {}^{2} + (2 - 2) {}^{2} }$

$\sqrt{(2 { )}^{2} +( 0) {}^{2} }$

$\sqrt{4 + 0}$

$\sqrt{4}$

$= 2$

$ab = 2$

BC=

$\sqrt{(3 - 4) {}^{2} + (0 - 2 ) {}^{2} }$

$\sqrt{ (- 1) {}^{2} + (- 2) {}^{2} }$

$\sqrt{1 + 4}$

$\sqrt{5}$

$bc = \sqrt{5}$

CD =

$\sqrt{(1 - 3) {}^{2} + (0 - 0) {}^{2} }$

$\sqrt{ (- 2) {}^{2} +( 0 ) {}^{2} }$

$\sqrt{4 + 0}$

$\sqrt{4}$

$= 2$

$cd = 2$

$\sqrt{(1 - 2) {}^{2} + (0 - 2) {}^{2} }$

AD=

$\sqrt{ (- 1) {}^{2} + (- 2) {}^{2} }$

$\sqrt{1 + 4}$

$\sqrt{5}$