Question

Please solve q 2
Solve this for x.....

Answer 1

$pq {x}^{2} - ( {p}^{2} + {q}^{2} )x + pq = 0 \\ pq {x}^{2} - {p}^{2} x - {q}^{2} x + pq = 0 \\ px(qx - p) - q(qx - p) = 0 \\ (px - q)(qx - p) = 0 \\ \\ x = \frac{p}{q} \: and \: \frac{q}{p}$
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Answer 2

Answer:

p/q, q/p

Step-by-step explanation:

Given Equation is pqx² - (p² + q²) x + pq = 0

⇒ pqx² - p²x - q²x + pq = 0

⇒ px(qx - p) - q(qx - p) = 0

⇒ (px - q)(qx - p) = 0

(i)

px - q = 0

px = q

x = q/p.

(ii)

qx - p = 0

qx = p

x = p/q.

Therefore, roots of the equation are q/p, p/q.

Hope it helps!