Please solve q.no. 8
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The ques should be AB⊥BD
Solving them
let x and y be 11a and 19a
then in ΔABD
11a+19a+90°=180° (angle sum property)
30a=90°
a=90°/30 = a=30°
∠x=33° (11a)
∠y=57°(19a)
as AB║BD
Then,∠ADC=∠DCE
∠DCE=65° (32+33)
:) Hope this helps!!!
Solving them
let x and y be 11a and 19a
then in ΔABD
11a+19a+90°=180° (angle sum property)
30a=90°
a=90°/30 = a=30°
∠x=33° (11a)
∠y=57°(19a)
as AB║BD
Then,∠ADC=∠DCE
∠DCE=65° (32+33)
:) Hope this helps!!!
Swastik500:
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