Question

Please solve Q23.Please help me friends

Answer 1

this answer may help you

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Answer 2

$\frac{1}{x - 1} - \frac{1}{ {x}^{} } = \frac{1}{x + 3} - \frac{1}{x + 4} \\ \frac{x - x + 1}{ {x}^{2} - x} = \frac{x + 4 - x - 3}{(x + 3)(x + 4)} \\ \frac{1}{ {x}^{2} - x} = \frac{1}{ {x}^{2} + 3x + 4x + 12} \\ {x}^{2} + 7x + 12 = {x}^{2} - x \\ 7x + x = - 12 \\ 8x = - 12 \\ x = \frac{ - 12}{8} = \frac{ - 3}{2}$