Question

Please solve q4. 3. I need it

Answer 1

Answer:

Step-by-step explanation:

let 4 consecutive nos be

a-3d,a-d,a+d,a+3d

sum=18

a-d+a+d=18

2a=18

a=9

product=45

a-3d)(a+3d)=45

(9-3d)(9+3d)=45

81-27d+9d^2+27d=45

9d^2=45-81

9d^2=-36

d^2=36/9

d^2=-

d=-2

4 consecutive terms are

a-3d=9-6=3

a-d=9+2=11......

sorry conginue