Please solve Q6 and Q7 with proper steps asap.
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HEYA...
HERE IS YOUR ANSWER---
A/C TO THEQUESTION ---
x^2 - x - 12 / x - 3 = 0
THEREFORE x -3 IS FACTOR...
NOW x - 3 =0
therefore vale of x = 3...[1]
now...BY DIVIDING THE POLYNOMIAL x^2 - x - 12 BY x - 3
WE GET THE QUOTIENT x +4
therefore value of x =
x - 4 = 0
x = -4
ALSO BY PUTTING THE VALUEOF 'x' AS 4 IN THE EQUATIONS GIVES ANSWER 0...
SO THE CORRECT OPTION WILL BE
[A] [-4,3]...[4,]
HOPE HELPED.
HERE IS YOUR ANSWER---
A/C TO THEQUESTION ---
x^2 - x - 12 / x - 3 = 0
THEREFORE x -3 IS FACTOR...
NOW x - 3 =0
therefore vale of x = 3...[1]
now...BY DIVIDING THE POLYNOMIAL x^2 - x - 12 BY x - 3
WE GET THE QUOTIENT x +4
therefore value of x =
x - 4 = 0
x = -4
ALSO BY PUTTING THE VALUEOF 'x' AS 4 IN THE EQUATIONS GIVES ANSWER 0...
SO THE CORRECT OPTION WILL BE
[A] [-4,3]...[4,]
HOPE HELPED.
anu522:
also mrk brainliest if helped
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