Question

please solve question 10

Answer 1

Step-by-step explanation:

I think so it is correct

Answer 2

Answer:

(p2-q2) x2+(q2-x2) x+(x2-p2) =0----------1

the sum of thr coeficient

(p2-q2) +(q2-r2) +(r2-p2) =0

x=1 is a root of ----1

(p2-q2) y+(r2-p2) y+q2-r2=0----------------2

p2-q2+r2-p2+q2-r2=0

y=1 is the root of ---2

therefore 1 is the common root of 1 and 2