Please solve question 16 with steps.
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Given : An isosceles triangle and angle between equal side lies between° 60 & 90°
To find : Choose correction about possible lengths of a
Solution:
As we know side opposite to greater angle is greater if
A = 60 deg then all Sides would be equal
as A > 60 ° hence Side of opposite to angle A is greater
=> a > b , c
Now if A = 90°
then b² + c² = a²
=> a² = 2b² = 2c²
=> a = √2b = √2c
but A < 90°
=> a < √2b , √2c
a > b , c & a < √2b , √2c
from the given option
c < a < √2c is correct option
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