Question

Please solve question 21 urgently!! I'll mark as brainliest.

Answer 1

heya here is ur ans pls mark it brainliest hope it works

By joining A and C, we get two triangles ABC and ACD.

Let

. . . pls refer to the attachment

Answer 2

Answer:

132 sq.units

Step-by-step explanation:

Given vertices are A(3,-1), B(9,-5), C(14,0) and D(9,19).

Here, x₁ = 3, y₁ = -1, x₂ = 9, y₂ = -5, x₃ = 14, y₃ = 0, x₄ = 9, y₄ = 19.

Now,

(i) Area of ΔABC:

= (1/2)[x₂(y₂ - y₃) + x₂(y₃ - y₁) + x₃(y₁ - y₂)]

= (1/2)[3(-5 - 0) + 9(0 + 1) + 14(-1 + 5)]

= (1/2)[-15 + 9 + 56]

= (1/2)[50]

= 25 sq.units.

(ii) Area of ΔACD:

= (1/2)[3(0 - 19) + 14(19 + 1) + 9(-1 - 0)]

= (1/2)[-57 + 280 - 9]

= (1/2)[214]

= 107 sq.units.

Therefore, Area of quadrilateral ABCD = 132 sq.units.

Hope it helps!