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The remained question:
x=1/2√3
Therefore, x^3 - 2x^2 - 7x + 5
= (1/2√3)^3 - 2(1/2√3)^2 - 7(1/2√3) + 5
= 1/24√3 - 2*1/12 - 7/2√3 + 5
= 1/24√3 - 1/6 - 7/2√3 + 5
=1/24√3 - 7/2√3 - 1/6 + 5
=(1 - 84)/24√3 + (-1+30)/6
=-83/24√3 + 29/6
= -83/24√3 * √3/√3 + 29/6
= -83√3/72 + 29/6
= 29/6 - 83√3/72
The remained question:
x=1/2√3
Therefore, x^3 - 2x^2 - 7x + 5
= (1/2√3)^3 - 2(1/2√3)^2 - 7(1/2√3) + 5
= 1/24√3 - 2*1/12 - 7/2√3 + 5
= 1/24√3 - 1/6 - 7/2√3 + 5
=1/24√3 - 7/2√3 - 1/6 + 5
=(1 - 84)/24√3 + (-1+30)/6
=-83/24√3 + 29/6
= -83/24√3 * √3/√3 + 29/6
= -83√3/72 + 29/6
= 29/6 - 83√3/72
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do all sum
oh sorry i forgot one. i am doing it now
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