Question

Please solve question 7 as soon as possible
I will mark it as braniliest answer if it is helpful to me​

Answer 1

Answer:

in triangle ACF AND BDE

AC=BD(GIVEN)

ANGLE ACF=ANGLE BDE(EACH 90°)

ANGLE CAF=ANGLE EBD (ALTERNATE ANGLES)

HENCE TRIANGLE ACF=BDE(ASA.. ANGLE SIDE ANGLE THEOREM)

THEREFORE, CF=DE(CPCT)

ACIIDB(CPCT)