Please solve question 8
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inthe the two cicles are congruent because their diameterr is equal.(i.e dc=ab=21cm)
area of shaded region=(area of square)-2(area of the semicircle)
=(21×21)-2(π×21²/8)
area of shaded region=94.63.
area of shaded region=(area of square)-2(area of the semicircle)
=(21×21)-2(π×21²/8)
area of shaded region=94.63.
akhilkick:
perimeterof shaded region=2*side+curved surface=2*21+66=174cm
therfore your required answer is 174cm
sorry for wrong answer
2*21+66= 174
How its 108
its 174
its not 108 because the above calculation is 2(21+66)=174
got it
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ABCD is square with sides 21cm ...and there are two semicircles...so the radius of the semicircles will be same...i.e.21/2...so the area of the two semicircles will also be same...so..area of the two semicircles DPC and APB=πr^2*2/2=πr^2=22/7*21/2*21/2=346.5cm^2..so now let us find the area of the square=21*21=441cm^2..so the area of the shaded region=441-346.5=94.5cm^2(ans)
you have to find perimeter
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