Physics, asked by goku9876, 11 months ago

Please solve question in this picture.Answer is option (d)

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Answers

Answered by siril
2

Let us assume that the particle is at rest.

Now, Let me solve this problem in 3 cases as depicted in the attachment below:

CASE 1:

When both S₁ and S₂ move in the same direction with an acceleration 4m/s². Here, the Relative acceleration ( .i.e, acceleration of S₂ with respect to S₁ as given in the options) between S₁ and S₂ is zero.

CASE 2:

When both S₁ and S₂ move in opposite directions, each with an acceleration of 4m/s². Here, the acceleration of S₂ with respect to S₁ becomes 8 m/s.

CASE 3:

In this case, both S₁ and S₂ are moving with an acceleration of 4m/s² but in directions other then the above ones. Here, depending on the angle between the acceleration vectors (or simply the angle between their direction of propagation), the acceleration of S₂ with respect to S₁ varies from 0 to 8 excluding both.

Please follow the attachment simultaneously... ↓↓

Hope it helps!!

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goku9876: Getting problem in understanding case 3
siril: wait i'll add another image for case 3
goku9876: Got it
goku9876: thank you very much
siril: welcome : )
Answered by Anonymous
3

Answer:

Correct answer is option(d). And for checking you can apply in all the sutuation comes.

Mark brainliest and follow me fast guys..

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