please solve question no.13 and 15
I WILL MARK AS BRAINIEST
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Hope it helps:).........
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Plz mark as brainliest
15) answer is products
13:
Let breadth =b
ATQ
Length =5+b
Perimeter of rectangle given=50
But since perimeter of rectangle =2(l+b)
2(5+b+b)=50
2*(5+2b)=50
10+4b=50
4b=40
b=10
Therefore length l =b+5
l=15
b=10
Area=l*b
Area=15*10=150cm^2
15) answer is products
13:
Let breadth =b
ATQ
Length =5+b
Perimeter of rectangle given=50
But since perimeter of rectangle =2(l+b)
2(5+b+b)=50
2*(5+2b)=50
10+4b=50
4b=40
b=10
Therefore length l =b+5
l=15
b=10
Area=l*b
Area=15*10=150cm^2
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