please solve question no 17
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Heya
_______________________________
a³ + b³ = ( a + b )³ - 3ab ( a + b )
Sin² x + Cos² x = 1
_______________________________
{ Sin² x + Cos² x }³ - 3 Sin² x × Cos² x { Sin²x + Cos² x }
=>
{ 1 } - 3 Sin²x × Cos²x { 1 }
= 1 - 3Sin²x × Cos² x
2)
Sin²x + ( 1 - Sin²x )²
=>
Sin²x + 1 + Sin⁴x - 2Sin²x
=>
Sin⁴x + 1 - Sin²x
Sin⁴x + Cos²x
_______________________________
a³ + b³ = ( a + b )³ - 3ab ( a + b )
Sin² x + Cos² x = 1
_______________________________
{ Sin² x + Cos² x }³ - 3 Sin² x × Cos² x { Sin²x + Cos² x }
=>
{ 1 } - 3 Sin²x × Cos²x { 1 }
= 1 - 3Sin²x × Cos² x
2)
Sin²x + ( 1 - Sin²x )²
=>
Sin²x + 1 + Sin⁴x - 2Sin²x
=>
Sin⁴x + 1 - Sin²x
Sin⁴x + Cos²x
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