Question

Please solve question no. 28

Answer 1

by rule of Ferraday sir ,
equivalent of oxygen = equivalent of silver

equivalent of silver = mass/(molar mass /n -factor )
=0.108/(108/1) = 0.108/108 =0.001
now,
equivalent of oxygen = 0.001
weight /equivalent wt = 0.001
n-factor of O2 × mole of oxygen = 0.001
2× mole of oxygen = 0.001
mole of oxygen =10^-3 x 0.5
mole of oxygen = 5× 10^-4
volume /22.4L =5 × 10^-4
volume = 112 x 10^-4 L
volume =11.2 cm³