Please solve question no. 3
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Area of given figure is : 261
First of all,
Construct a line CE perpendicular to AB
Then area of square AECD= 23×9 =207m^2
Then , area of triangle ECB AD=CE=9m
by Pythagoras theorem, we get EB=12m
by formula 1/2×base×height we get area of triangle = 54m^2
Area of square + area of triangle = ( 207 + 54)m^2
= 261m^2
is it right??
First of all,
Construct a line CE perpendicular to AB
Then area of square AECD= 23×9 =207m^2
Then , area of triangle ECB AD=CE=9m
by Pythagoras theorem, we get EB=12m
by formula 1/2×base×height we get area of triangle = 54m^2
Area of square + area of triangle = ( 207 + 54)m^2
= 261m^2
is it right??
Astha01:
Where is the solution
Yaa thank you so much:)
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