Math, asked by brain80, 1 year ago

please solve question number 13 plz

Attachments:

Answers

Answered by aryan78243
1
the number of articles are 30 ...bought at 450 each
one third to be sold at 6% kiss each
1/3×30=10 articles
6% loss = 94/100×450=Rs 423

the 10 articles sold at 423 each will be =4230

The initial price of all the 330 was =450×30=13500
profit of 10% on The whole would mean 110%of 13500=110/100×13500
=14850
to find the price at which the remaining 2/3 are sold subtract 4230 from 14850
14850-4230=10620

therefore the remaining 20 must be sold at 10620
men price for it would be 10620/20=531

therefore the rest have to be sold at Rs 531

l think it's help you please mark me as brainiest
Similar questions