Question

please solve question number 19

Answer 1

$\sqrt{2} x + \sqrt{3} y = 0 \\ \\ \sqrt{2}x = - \sqrt{3}y \\ x = \frac{ - \sqrt{3} y}{ \sqrt{2} } \\ \sqrt{3} x - \sqrt{8} y = 0 \\ put \: value \: of \: x \: in \: this \: eq\\ \sqrt{3} ( \frac{ - \sqrt{3}y }{ \sqrt{2} } ) - \sqrt{8} y = 0 \\ \frac{ - 3y}{ \sqrt{2} } - 2\sqrt{2} y = 0 \\ \frac{ - 3y - 2 \sqrt{2} \sqrt{2} y}{ \sqrt{2} } = 0 \\ - 3y - 4y = 0 \\ - 7y = 0 \\ y = 0 \\ \sqrt{2} x + \sqrt{3} \times 0 = 0 \\ \sqrt{2} x = 0 \\ x = 0$