Please solve question number 4
Attachments:
Answers
Answered by
2
( a) MOLARITY = MOLES OF SOLUTE / VOLUME OF SOLUTION
Moles of NaCl = Mass / Molar mass
Moles of NaCl = 5. 85 / 58.5 = 0.1
Molarity = 0.1 / 200 ml = 0.0005 M
(b) Moles of NaBr = 20.6/103 = 0.2
MOLARITY = 0.2 / 500 = 0.0004 M
Moles of NaCl = Mass / Molar mass
Moles of NaCl = 5. 85 / 58.5 = 0.1
Molarity = 0.1 / 200 ml = 0.0005 M
(b) Moles of NaBr = 20.6/103 = 0.2
MOLARITY = 0.2 / 500 = 0.0004 M
Similar questions