the first and the last term of an ap are 7 and 49 respectively if sum of all its terms is 425 it's common difference
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5
data wrong if
I think sn=420
then
sn=n/2(a+l )
420=n/2(7+49)
420=28n
n=15
Now
an=a+(n-1)d
49=7+(15-1)d
42=14d
d=3
I hopes it will hepl u
I think sn=420
then
sn=n/2(a+l )
420=n/2(7+49)
420=28n
n=15
Now
an=a+(n-1)d
49=7+(15-1)d
42=14d
d=3
I hopes it will hepl u
Answered by
3
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