Question

please solve question number 5;
I will make the correct answer as brainliest.

Any spam answer will be reported

Answer 1

sin=5/13 cos=12/13 tan =5/12
cosec =13/5 cot =12/5

Answer 2

here I am writing Theta as A, because it is difficult for me to write theta always.

(5).

Given SecA = 13/12.

We know that cosA = 1/secA

                                 = 1/13/12

                                 = 12/13.





We know that sin^2 A = 1 - cos^2 A
 
                                      $= 1 - ( \frac{12}{13} )^2$

                                      $= \frac{169 - 144}{169}$

                                     $= \frac{25}{169}$

                          Sin A = 5/13.    




We know that Tan A = sinA/cosA

                                  $= \frac{5}{13} * \frac{13}{12}$

                                 $= \frac{5}{12}$




We know that Cosec A = 1/sinA

                                       = 1/5/13

                                       = 13/5.


We know that cot A = 1/tanA

                                  = 1/5/12

                                  = 12/5.



Therefore,

$cos A = \frac{12}{13}$

$sin A = \frac{5}{13}$

$Tan A = \frac{5}{12}$

$cosec A = \frac{13}{5}$

$cot A = \frac{12}{5}$



Hope this helps!