Physics, asked by ShivamKashyap08, 1 year ago

Please solve questions no 62.
only correct answers accepted.
Need Explanation also. ​

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Answers

Answered by AleXXa
10

ANSWER:-

initially energy stored in springs = P.E = 1/2 K1x² + 1/2K2 x²

after stretching, this P.E will convert into K.E

by applying law of conservation of energy.

1/2MV² = 1/2* K1*x² + 1/2*K2*x²

MV² = K1*x² + K2*x²

V² = x²(K1+K2)/m

V = x √(2K')/m

as, it is parallel combination of springs so

K equivalent = K1 + K2 = K'

x = displacement here

Answered by Anonymous
7

Answer:

see the attachment for the answer

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