Question

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Answer 1

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Given,

(For Nucleus)

u =0 (stationary )

P = mu =0

●【Nucleus decays by emitting proton with speed v to form new nucleus with speed u】●

Let the mass of NUCLEUS be m

Number of nucleus in new nucleus =[A-1]

(after decay),

Momentum = NO° of nucleus × mv

p = (A -1) × m (-u)

u is negative because new nucleus and proton travels in opposite direction.

● Total momentum after decay = momentum of proton + momentum of new nucleus●

P = mv + [(A-1)m(-u)]

P = mv + [-(A-1)mu]

p = mv - (A-1)mu

Now, apply law of conservation of momentum

P(final) = p (initial)

mv - (A-1)mu =0

【initial momentum is 0 】

mv = (A-1)mu

v = (A-1)u

●◆option 2 is correct ◆●

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Answer 2

Explanation:

opton 2 is correct Answer

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